// Test for a fuzzer: must find the case where a particular basic block is
// executed many times.
#include <iostream>
extern "C" int LLVMFuzzerTestOneInput(const uint8_t *Data, size_t Size) {
int Num = 0;
for (size_t i = 0; i < Size; i++)
if (Data[i] == 'A' + i)
Num++;
if (Num >= 4) {
std::cerr << "BINGO!\n";
exit(1);
}
return 0;
}