/* * Copyright (C) 2008 The Android Open Source Project * All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * * Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * * Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in * the documentation and/or other materials provided with the * distribution. * * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS * "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT * LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS * FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE * COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, * BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS * OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED * AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, * OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT * OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF * SUCH DAMAGE. */ #include <stddef.h> #include <stdint.h> #include <ctype.h> static inline int digitval(int ch) { unsigned d; d = (unsigned)(ch - '0'); if (d < 10) return (int)d; d = (unsigned)(ch - 'a'); if (d < 6) return (int)(d+10); d = (unsigned)(ch - 'A'); if (d < 6) return (int)(d+10); return -1; } uintmax_t strntoumax(const char *nptr, char **endptr, int base, size_t n) { const unsigned char* p = (const unsigned char *)nptr; const unsigned char* end = p + n; int minus = 0; uintmax_t v = 0; int d; /* skip leading space */ while (p < end && isspace(*p)) p++; /* Single optional + or - */ if (p < end) { char c = p[0]; if ( c == '-' || c == '+' ) { minus = (c == '-'); p++; } } if ( base == 0 ) { if ( p+2 < end && p[0] == '0' && (p[1] == 'x' || p[1] == 'X') ) { p += 2; base = 16; } else if ( p+1 < end && p[0] == '0' ) { p += 1; base = 8; } else { base = 10; } } else if ( base == 16 ) { if ( p+2 < end && p[0] == '0' && (p[1] == 'x' || p[1] == 'X') ) { p += 2; } } while ( p < end && (d = digitval(*p)) >= 0 && d < base ) { v = v*base + d; p += 1; } if ( endptr ) *endptr = (char *)p; return minus ? -v : v; }